In how many ways can 3 person study groups be selected from a class of 25 students
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2 question says how many 3% committee can be selected from a fraternity with 25 members the option 15625 13820 375 so the method of finding out out is pretty simple it is just 2553 which means the number of combinations which can be formed of 3 people from 25 people which is given by 25 factorial upon 3 factorial in 222 factorial which comes out to be 25 into 24 into 23 upon 3 into 2 ok 22 Studio cancel the 22 factorial on the numerator and so this comes out with 25 into 24 into 23.35 12 which is 3 into 2 into 1 you can write Show into one human was frightened because it does not collect any difference in the Calculation and so this comes out to be 2300 it is basically the number of ways from in which three members can be selected from from 25 members and so this is a very basic function of combination combination coronavirus found it up with this formula and factorial upon in in factorial into a minus b upon our factory in 21 - 8 factorial thank you
Question 453172: In a class of 25, How many ways can a group of five students be selected? Answer by jim_thompson5910(35256) You can put this solution on YOUR website!
 Plug in and Subtract to get 20 Expand 25! Expand 20! Cancel Simplify Expand 5! Multiply 25*24*23*22*21 to get 6,375,600 Multiply 5*4*3*2*1 to get 120 Now divide So 25 choose 5 (where order doesn't matter) yields 53,130 unique combinations So there are 53,130 different ways to form a group of 5 people. How many groups of three students can be chosen from a class of 15 students?The number of 3-student groups that can be made from the 15-student class is given by 15 x 14 x 13 = 2,730 combinations.
How many ways can a group of 5 be chosen from 25?Expand 25! Expand 20! Expand 5! So there are 53,130 different ways to form a group of 5 people.
How many teams of 3 students can be chosen from a group of 12 students?12-3)!) = 12! / 3! * 9! So there are 220 possible combinations of 3 people chosen from a group of 12.
How many different ways are there to select two class representatives from a class of 25 students?No. of ways = 24C2 = (24∗23∗22!) / (2! ∗22!) So, there are 276 possible particular person is never selected.
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